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Configuration = 107
cycles = (10 6 1 9 4)(8 5 2 7 3)

a = 3, b = 5, c = 7
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cycles = (10 4 1 9 6)(8 3)(7 2)(5)

a = 4, b = 6, c = 10
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cycles = (10)(9)(8)(7 4 1)(6 3)(5 2)

a = 3, b = 5, c = 6
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cycles = (10)(9)(8)(7 5 1)(6 2 3)(4)

a = 2, b = 3, c = 6
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cycles = (10)(9)(8)(7 4 1)(6)(5)(3)(2)